17g^2+15g-2=0

Solution for 17g^2+15g-2=0 equation:

17g^2+15g-2=0

a = 17; b = 15; c = -2;
Δ = b2-4ac
Δ = 152-4·17·(-2)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-19}{2*17}=\frac{-34}{34}
=-1
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+19}{2*17}=\frac{4}{34}
=2/17
$